All categories

3 years ago

Any help would be great. If you could explain this a little better it’d be much appreciated

Mathematics

1 answer:

Mariana [72]3 years ago

8 0

Answer:56g^8

Step-by-step explanation:

the variable has the same exponent so just add

56g^8

You might be interested in

the ratio of stars to stripes is 50 to 13. If there were 400 stars in the parade, how many stripes were there?

Black_prince [1.1K]

I believe it's 104. You would set it up as a fraction so:
50/13 and 400/x.
Then you would cross multiply so 13x400 is 5,200. So this divided by 50 = 104. Hope I helped!

5 0

3 years ago

PLEASE HELP!!!!!!!

crimeas [40]

Answer:

24.5

Step-by-step explanation:

❤❤❤❤❤❤❤

plz give brainliest

7 0

3 years ago

Can someone plz help me with this one problem plz!!!

kondor19780726 [428]

Answer:

<h2>25 square inches </h2>

Step-by-step explanation:

Given, 

Parallel sides of the trapezium = 3in, 7in

Height of the trapezium = 5in

Therefore, 

Area of the trapezium

$= \frac{1}{2} \times sum \: of \: parallel \: sides \times height$

$= \frac{1}{2} \times (7 + 3)in \times 5in$

$= \frac{1}{2} \times 10in \times 5in$

= 5in × 5in

$= {25in}^{2}$

Hence,

Area if the trapezium is 25 square inches (Ans)

8 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago

PLEASE HURRY! If the triangle on the grid below is translated by using the rule (x, y) right-arrow (x minus 2, y + 2), what will

Romashka [77]

Answer:

-4 pretty sure

Step-by-step explanation:

8 0

3 years ago