Answer: 6x^2 -8x +2
Step-by-step explanation:
The area of a rectangle is just length multiplied by width so would have:
Area = length x width = (6x-2)(x-1) = 6x^2 -8x +2.
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
They will each get 1 banana can i get brainiest please i was first and i barley have any
Answer:
B
Step-by-step explanation:
Basically, this question is asking the legs of the triangle shown in the graph.
In this right triangle, there are 2 legs and one of them is 6400 meters. We were asked to find out the length of the other led. And we know the angle is 16.5 deg.
Using Tangent to find out:
set the length of the other leg is x meters.
tan(16.5) = 6400/x
x= 6400/tan(16.5)
x= 21606 m
Https://www.symbolab.com/solver/function-asymptotes-calculator this is a good asymptote calculator
