1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
X= 5 divided by 2. Subtract the 9 from the 24 and divide by the 6.
Answer:
x^2 + 8x + 16
Step-by-step explanation:
(x + 4) (x+ 4) multiply x by x and x by 4.
x^2 + 4x
Then multiply 4 by x and 4 by 4.
4x + 16
Then combine like terms.
x^2 + 4x + 4x +16
x^2 + 8x + 16
Answer:
C
Step-by-step explanation:
This is a stem and leaf plot. If you don't know what a stem and leaf plot is, try searching it before coming back and viewing the solution. I also see an "example" button. It might help to hit that too.
First, we sort the list of numbers. Here is what we get:
64, 66, 67, 68, 69, 74, 75, 76, 78, 79
Here, the stems are the tens digits and the leaves are the ones digits.
Therefore, for the stem 6, the leaves are:
4, 6, 7, 8, 9
For the stem 7, the leaves are:
4, 5, 6, 8, 9
The answer, I believe, is C
