Round 306.9 to 307 then divide by 6.4 then you have your answer
Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
Answer is 34.96$ for the final cost.
Answer:
yes I try but not any solution come
please mark me brainliest and follow me my friend.
Answer:
It would take Brennan 4 track practice runs.
Step-by-step explanation:
He has already run 16 miles and needs to run 28 in total. If we are counting the 16 in the 28 miles, he would need to run only 12 more to reach his goal. And if he runs 3 miles a run, it would take him about 4 runs to finish his 28-mile goal.
(28-16=12 and 12/3=4)
