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Fittoniya [83]
3 years ago
11

Which is a physical property of matter?

Chemistry
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

volume

Explanation:

IrinaK [193]3 years ago
6 0

Answer:

D

Explanation:

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Dependent variable: If calcium is given, then bone strength will increase.

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Are there any vegetarian Italian Sausages?
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Alright, now you actually have an aqueous solution of your salt! Though perhaps not all of the salt has dissolved yet, but we'll
erica [24]

If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

<h3>What is concentration?</h3>

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

Learn more about concentration:brainly.com/question/10725862

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7 0
2 years ago
Describe a proton, neutron, and electron. Where are these particles located inside an atom.
Natali5045456 [20]
A proton is a positively charged particle found within the nucleus of an atom, a neutron carries no charge and is also found in the nucleus. An electron is a very small negatively charged particle found in the outer "shells" or orbitals of the atom.
4 0
3 years ago
Read 2 more answers
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
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