1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetllana [295]
2 years ago
13

1. What is the molar mass of silicon?

Chemistry
1 answer:
hodyreva [135]2 years ago
8 0

Answer:

Si = 28

2) = 148

Explanation:

You might be interested in
Hi I like a guy (He knows I like him too cause my friend told him) but me and this guy are really good friends how do I deal wit
kirza4 [7]

Answer:

Explanation:

When you start to feel you are desiring more than just a casual friendship with your best friend and you’re not sure what to do next, let me offer you some advice that could strengthen both your relationship and your love for each other.

First, don’t rush into a romantic relationship with your best friend…many times people confuse love with that other kind of caring love you feel for all of your other friends.

Second, don’t spill your guts right away. You might feel like you have to share all your thoughts and feelings with the other person as soon as you start to feel something. That’s usually a mistake.

8 0
2 years ago
Convert a speed of 259 cm/s to units of inches per minute. Also, show the unit analysis by dragging components into the unit‑fac
igomit [66]

Answer:

6118.11\frac{in}{min}

Explanation:

Hello,

In this case, by knowing that 1 inch equals 2.54 cm and 60 seconds equals 1 min, the resulting value results:

=259\frac{cm}{s}*\frac{1in}{2.54cm}*\frac{60s}{1min}\\   \\=6118.11\frac{in}{min}

Best regards.

5 0
3 years ago
An iron ore contains 39% Fe2O3 by mass. What is the maximum mass of iron that can be recovered from 13.2 kg of this ore?
Mars2501 [29]

Answer:

3.6036

Explanation:

0.39 * 13.2 = 5.148

5.148 * 0.7 = 3.6036

Fe2O3 = 0.7

6 0
3 years ago
What is a hypothesis?
gladu [14]

Answer: a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation: definition

3 0
3 years ago
How many grams of mercury can be produced if 18.0 g of mercury (11) oxide decomposes?
NARA [144]

Answer:

18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury

Explanation:

Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.

The decomposition of mercury oxide is given by the chemical equation below:

2HgO ----> 2Hg + O₂

2 moles of HgO decomposes to produce 1 mole of Hg

2 moles of HgO has a mass of 433.2 g

433.2 g of HgO produces 216.6 g of Hg

18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg

Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury

3 0
2 years ago
Other questions:
  • The pH of a 0.25 M (aq) solution of hydrofluoric acid, HF, at 25C is 2.03. What is the value of Ka for HF? Pls show all mathemat
    5·1 answer
  • What does the atomic number of an element tell you about the element?
    13·1 answer
  • An aspirin tablet contains 325 mg acetylsalicylic acid. How many acetylsalicylic acid molecules does it contain?
    13·1 answer
  • How does changing the temperature affect the chemical reaction?
    9·1 answer
  • A scientist obtains the number 1250.37986 on a calculator. If this number actually has four (4) significant figures, how should
    13·2 answers
  • Which particle has 2 neutrons
    13·2 answers
  • Which of the following include exact numbers?
    15·2 answers
  • If you take Organic Chemistry Laboratory (CHM2211L) you will learn the term reflux. A reaction is considered to be at reflux whe
    13·1 answer
  • Iron metal can be obtained from iron ore, iron (III) oxide. When the iron (III) oxide is reacted with carbon monoxide gas it for
    12·1 answer
  • a gas exerts a pressure of 1.00 atm at 273 K. At what tempreture the gas exerts a pressure of 4.00 atm.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!