Answer:
Check explanation
Explanation:
From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.
Molar mass of benzene,C6H6= 78.11236 g/mol.
Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.
STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.
Using the formula below;
Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.
=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.
= 8.175 J.
= 0.008175 kJ.
STEP TWO (2): ENERGY OF HEATING THE LIQUID.
It can be calculated from the formula below;
Energy= heat capacity (J/g.K) × mass of benzene× (∆T).
= 1.63 J/g.K × 64.7 × (41.9-33.2).
= 917.5J.
= 0.9175 kJ.
Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.
= 0.008175+ 0.9175.
= 0.93kJ
Approximately, 1 kJ
Answer:
NaHCO3 → H2O + CO2 + Na2CO3
Explanation:
Hello!
First, HNO₃ dissociates in the following way:
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
Next, there is a neutralization reaction with Methylamine:
H⁺(aq) + CH₃NH₂(aq) → CH₃NH₃⁺(aq)
Finally, the formed methylammonium ion weakly dissociates in the following way:
CH₃NH₃⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CH₃NH₂ (aq)
From this sequence of reactions, we can see that the resulting solution would be slightly more acidic than the initial one, as the buffer solution resists the addition of strong acid.
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