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Musya8 [376]
3 years ago
11

Solve by using substitution:

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer: no solutions

\left \{ {{y=6x + 1} \atop {y=-2+ 6x}} \right.\\\\\left \{ {{-2+6x=6x+1} \atop {y=-2+6x}} \right.\\\\\left \{ {{6x-6x=1+2} \atop {y=-2+6x}} \right.\\\\\left \{ {{0=3} \atop {y=-2+6x}} \right.

but 0 ≠ 3 =>  There are no values ​​for x and y => no solutions

Step-by-step explanation:

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<h3>Answer:  161 degrees</h3>

=========================================================

Explanation:

Line AE is a tangent while line AU is a secant. The angle formed by the secant and tangent lines connects with the arcs through this formula

secant tangent angle = (larger arc - smaller arc)/2

More specifically, we can say:

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