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LuckyWell [14K]
2 years ago
14

-15(-12-6) what is this

Mathematics
1 answer:
fenix001 [56]2 years ago
7 0
<h2>Answer: 270</h2>

...................................................                                              

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Need help on math again plz
EastWind [94]

Answer:

Socratic app

Step-by-step explanation:

it will help you

7 0
3 years ago
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ALMN is a right triangle.
GarryVolchara [31]

Answer:

this is true since a right triangle has one side that is 90 degrees

Hope This Helps!!!

4 0
3 years ago
The area (in square inches) of a rectangle is given by the polynomial function A(p) = p2 + 9p + 20. If the length of the rectang
boyakko [2]

Answer:

Width = p + 4

Step-by-step explanation:

Given

Area = p^2 + 9p + 20

Length = p + 5

Required

Determine the width

The area of a rectangle is:

Area = Length * Width

This gives:

p^2 + 9p + 20= (p+5)* Width

Expand

p^2 + 4p + 5p + 20= (p+5)* Width

Factorize

p(p + 4) + 5(p + 4)= (p+5)* Width

(p + 5) (p + 4)= (p+5)* Width

Divide both sides by p + 5

p + 4= Width

Width = p + 4

7 0
3 years ago
Solve the equation : x^(2)+5=3(x^(2)-3)
Fittoniya [83]

Answer:

x = ± 2

Step-by-step explanation:

Given

x² + 5 = 3x² - 3 ( subtract x² + 5 from both sides )

0 = 2x² - 8 ( add 8 to both sides )

8 = 2x² ( divide both sides by 2 )

4 = x² ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

6 0
4 years ago
Consider the sequence 3, 6, 12, 24, 48, .... (a) Write a recursive rule to represent the sequence. (b) Write an explicit rule to
saveliy_v [14]

Answer:

  a. a[1] = 3; a[n] = 2a[n-1]

  b. a[n] = 3·2^(n-1)

  c. a[15] = 49,152

Step-by-step explanation:

Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.

The first term is 3, and the common ratio is 2.

<h3>(a)</h3>

The recursive rule is ...

  a[1] = 3

  a[n] = 2×a[n-1]

__

<h3>(b)</h3>

The explicit rule is ...

  a[n] = a[1]×r^(n-1)

  a[n] = 3×2^(n-1)

__

<h3>(c)</h3>

The 15th term is ...

  a[15] = 3×2^(15-1) = 3×2^14

  a[15] = 49,152

5 0
3 years ago
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