Sela had 40 coins 4 months ago because 240 divided by six is 40.
8. A
9. C
10. D
Those are the answers
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
{−5}
hope it helps, tell me if im wrong! be safe! :D
Answer: 6
I don't know what a hundred chart is but every prime bigger than 3 is one more or one less than a multiple of six.
The possible remainders when we divide by six are 0,1,2,3,4 and 5. The remainders 0,2,3, and 4 all indicate we have a multiple of two or three, so composite if bigger than 3. So the only possible remainders are 1 and 5, which are one more and one less than a multiple of six respectively.
