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KengaRu [80]
3 years ago
9

The profit that the vendor makes per day by selling x pretzels is given by the function P(x) = - 4x +2,400x - 400. Find the numb

er of pretzels that must be sold to maximize profit.
O A. 359,600 pretzels

OB. 300 pretzels

OC. 600 pretzels
Mathematics
1 answer:
never [62]3 years ago
8 0

We have been given that the profit that the vendor makes per day by selling x pretzels is given by the function P(x)=-4x^2+2400x-400. We are asked to find the number of pretzels that must be sold to maximize profit.

First of all, we will find the derivative of our given function.

P'(x)=-4\cdot 2x^{2-1}+2400

P'(x)=-8x+2400

Now, we will find the critical point by equating derivative with 0 as:

-8x+2400=0

-8x+2400-2400=0-2400

-8x=-2400

\frac{-8x}{-8}=\frac{-2400}{-8}

x=300

Therefore, the company must sell 300 pretzels to maximize profit and option B is the correct choice.

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The minimum number of shirt they will sell to make the given profit is 192 shirts

<h3>Inequality expression</h3>

Inequalities are equations not separated by an equal sign.

If a cheerleading team plans to sell t-shirts as a fundraiser and the teams goal is to make profit of at least $1248 with each t-shirt sold at $6.50, then the equation required is;

6.50t ≥ 1246

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Hence the minimum number of shirt they will sell to make the given profit is 192 shirts

Learn more on inequality here: brainly.com/question/11613554

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Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

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