Ask question

Ask question

All categories

3 years ago

15

Kendrick and Perla spend a total of $92 at an amusement park. They spend $15 on parking, $13 at lunch, and the rest on two admis

sion tickets.
How much does each admission ticket cost, in dollars?

2 answers:

Lunna [17]3 years ago

8 0

Answer:

Each admission ticket costs $32

Step-by-step explanation:

92 - 15 -13 = 64

64/2 = 32

tangare [24]3 years ago

5 0

Each ticket would cost 5!!!!!

You might be interested in

Urgent help please! Answer any of the questions!

kiruha [24]

#1. x = - (2y) / (1-y)

#2. x = (-4y-3)/(1-y)

I can't really see the other questions, so I only did the first two. Hope this helps!

8 0

2 years ago

margo borrows $900.00 and must pay it back with 6% interest after 7 months. what is the total amount margo will pay back ?

ozzi

Answer:

$954

Step-by-step explanation:

6% = 0.06

Adding 1 to the interest makes it so it’s added to the original amount.

$900 x 1.06 = $954

8 0

2 years ago

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}$

$13C_5=\frac{154440}{120}$

$13C_5= 1287$

8 0

3 years ago

Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 5(cos(25) + isin(25)) z2 = 2(cos(80) +

zmey [24]

solution:

Z1 = 5(cos25˚+isin25˚)

Z2 = 2(cos80˚+isin80˚)

Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)

Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }

Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}

(i^2 = -1)

Cos(A+B) = cosAcosB – sinAsinB

Sin(A+B) = sinAcosB + cosAsinB

Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)

Z1.Z2 = 10(cos105˚+ isin105˚)

5 0

3 years ago

Find the area of the shaded region in each of the following figure all unit are in cm

vodomira [7]

1st problem:
A = 630 cm

2nd problem:
A = 104 cm

All I can see on the picture you provided.

7 0

3 years ago