A fire burned a square - shaped forest 14mi on a side the area is ?

Mathematics

2 answers:

Tpy6a [65]2 years ago

8 0

A square has all sides of the same length. This means that the length and width are both 14 miles. The area of a square is Length times width, or 14 times 14. This comes out to be 196 miles squared

Nitella [24]2 years ago

3 0

The area is the nuber times the sides which would be 14 times 4, which equals 56

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Which is the best approximation of PX

Aleks [24]

Answer:

We now want to ﬁnd the best approximation to a given function. This fundamental problem in Approximation Theory can be stated in very general terms. Let V be a Normed Linear Space and W a ﬁnite-dimensional subspace of V , then for a given v ∈ V , ﬁnd w∗∈ W such that kv −w∗k ≤ kv −wk, for all w ∈ W.

Step-by-step explanation:

8 0

2 years ago

The table below represents a linear function.

ohaa [14]

(-1,5)(1,9)
slope = (9 - 5) / (1 - (-1) = 4 / (1 + 1) = 4/2 = 2

y = mx + b
slope(m) = 2
use any of ur points in the table....(1,9)...x = 1 and y = 9
now we sub ad find b, the y int
9 = 2(1) + b
9 = 2 + b
9 - 2 = b
7 = b

so ur equation of the table is : y = 2x + 7.....where the slope = 2 and the y intercept = 7

so, the equation with the greater slope and the greater y int is :
y = 3x + 7.5....this has a slope of 3 and a y int of 7.5

8 0

3 years ago

Help pls im being timed

Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: $(hypothenuse)^2=(leg_1)^2+(leg_2)^2$ . And the main trigonometric ratios are:

$sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\$

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

$sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4$

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

$sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}$