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fgiga [73]
3 years ago
6

The point D(-3, 1) is reflected over the x-axis. What are the coordinates of the resulting point, D′?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer:

The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same.

Step-by-step explanation:

For example, when point P with coordinates (5,4) is reflecting across the X axis and mapped onto point P', the coordinates of P' are (5,-4).

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The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu
Slav-nsk [51]
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is 25in^{2}, and its volume is 250in^{3}. We also know that the area of the larger figure is 36in^{2}; since we don't now its volume, lets represent it with X:
\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} 
\frac{25}{36} = \frac{250}{X}
X= \frac{(250)(36)}{25}
X=360

We can conclude that the volume of the larger figure is 360in^{3}; therefore, the correct answer is a.
6 0
3 years ago
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Round 87590 is nearest 1000 you will get​
Diano4ka-milaya [45]

Answer:

88,000

Step-by-step explanation:

The number in the thousands is 7. If we look at the hundreds, it has a 5. 5 or more means to round up. So, rounding up the 7 gives us 8. Then, we make all the numbers past the 1000's place 0's. So, we are therefore left with 88,000.

Hope this helps! :D

3 0
2 years ago
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Which of the following diagram represent a relation that is not a function​
andrew11 [14]
You didn’t even post a diagram

which of the following diagram represent a relation that is not a function
8 0
3 years ago
-3(8n+10) <br> distributive property
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6 0
3 years ago
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1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
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