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shusha [124]
3 years ago
11

You run 20 laps in 6 minutes. your friend runs 30 laps in 9 minutes. are you the rates equivalent

Mathematics
2 answers:
Law Incorporation [45]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

if you break it down 2/6 = 3/9 20 divided by 6 equals 3.333... 30 divided by 9 equals 3.333...

Bad White [126]3 years ago
4 0

Answer:

YES

Step-by-step explanation:

BECAUSE I KNOW EVERYTHING!!!!!!!!!!!!!!!!!!!!

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Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
2 years ago
How would you measure the volume of a cardboard shoebox
Nina [5.8K]

-- Measure the length of the box.
-- Measure the width of the box.
-- Measure the height of the box.
-- Make sure all 3 measurements are in the same units.

-- Multiply (length) x (width).

-- Take that answer and multiply it by (height).

-- You now have the volume of the box.

6 0
3 years ago
N+16=9 solve for variable
Aleks [24]

Answer:

N= -7

Step-by-step explanation:

N+16=9

subtract 16 from both sides

N= -7

8 0
2 years ago
The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find
dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean(\mu) of 2500 hours and standard deviation(\sigma) of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: Z=\dfrac{X-\mu}{\sigma}

For X = 2470

Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0
2 years ago
I really need the help with this multiple choice question for geometry.
prisoha [69]

Answer:

  A.  50°

Step-by-step explanation:

The external angle ACB created by tangents CA and CB is the supplement of arc AB it intercepts.

  ∠ACB = 180° -AB

  ∠ACB = 180° -130°

  ∠ACB = 50°

4 0
1 year ago
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