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ohaa [14]
2 years ago
11

What is the mean absolute deviation of the following data set

Mathematics
1 answer:
tatuchka [14]2 years ago
4 0

Answer:

4.32

Step-by-step explanation:

First, we have to find the mean of the data set.

16, 11, 9, 12, 11, 10, 10, 8, 15, 0, 2, 15, 14, 7, 11, 5, 14, 20, 3, 11, 13, 7, 0, 5, 21 all added together equals 250. 250 divided by 25 = 10. So 10 is the mean.

Now we have to find the absolute distances of each number from the mean.

16 - 10 = 6... 11 - 10 = 1... so on, giving us this -->

6, 1, 1, 2, 1, 0, 0, 2, 5, 10, 8, 5, 4, 3, 1, 5, 4, 10, 7, 1, 3, 3, 10, 5, 11

Finally, we have to find the mean of the distances (which is done by adding all the numbers above and dividing the sum by the number of values there are).

108 divided by 25 = 4.32.

So, 4.32 is the mean absolute deviation (MAD) of the following data set.

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How many 4-digit odd numbers can you make using the digits 1 to 7 if the numbers must be less than 6000? No digits are repeated.
bixtya [17]

Answer:

Step-by-step explanation:he first digit must be a 6, 7, or 8, because the number has to be bigger than 6,000.

The last digit must be a 1, 3, 5, or 7, because the number has to be odd.

So if the first digit is 6 or 8, there are 4 odd-number options for the last digit. If the first digit is a 7, then there are only 3 options for the last digit, as 7 can’t be used twice.

The other two digits can be anything that’s not already used. So for each first-and-last combination of digits mentioned above, there will be six options available for one of the middle digits, and then for each of those 3-digit combinations, five options will be available for the final remaining digit.

At this point, we have everything we need to express this as an equation:

x = (2 x 4 + 1 x 3) x 6 x 5

And then we can simplify and solve:

x = (8 + 3) x 30

x = 11 x 30

x = 330

6 0
3 years ago
Drag each tile to the correct box. Not all tiles will be used.
Alina [70]

Answer:

3rd box, last box, 2nd box, 5th box in that order

Step-by-step explanation:

PEMDAS

7 0
3 years ago
Read 2 more answers
The perimeter of a rectangle garden is 364 feet. If the width of the garden is 85 feet, what is it length?
kherson [118]

P=2(L+W)

P=364

L=99

sub and find W

364=2(99+W)

divide both sides by 2

182=99+w

subtract 99 from both sides

83=W

w=83ft

6 0
2 years ago
The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from
Vinvika [58]

Answer:

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

df=n_1 +n_2 -2=13+19-2=30  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

\bar X_{1}=810 represent the mean for sample 1  

\bar X_{2}=770 represent the mean for sample 2  

s_{1}=67 represent the sample standard deviation for 1  

s_{2}=56 represent the sample standard deviation for 2  

n_{1}=13 sample size for the group 2  

n_{2}=19 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=13+19-2=30  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

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3 years ago
-3 1/2 + -2 + 4 1/4 = ????
mylen [45]

Answer:

-1 1/4

Step-by-step explanation:

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