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ohaa [14]
2 years ago
11

What is the mean absolute deviation of the following data set

Mathematics
1 answer:
tatuchka [14]2 years ago
4 0

Answer:

4.32

Step-by-step explanation:

First, we have to find the mean of the data set.

16, 11, 9, 12, 11, 10, 10, 8, 15, 0, 2, 15, 14, 7, 11, 5, 14, 20, 3, 11, 13, 7, 0, 5, 21 all added together equals 250. 250 divided by 25 = 10. So 10 is the mean.

Now we have to find the absolute distances of each number from the mean.

16 - 10 = 6... 11 - 10 = 1... so on, giving us this -->

6, 1, 1, 2, 1, 0, 0, 2, 5, 10, 8, 5, 4, 3, 1, 5, 4, 10, 7, 1, 3, 3, 10, 5, 11

Finally, we have to find the mean of the distances (which is done by adding all the numbers above and dividing the sum by the number of values there are).

108 divided by 25 = 4.32.

So, 4.32 is the mean absolute deviation (MAD) of the following data set.

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Step-by-step explanation:

<u>Step1:</u>-

marginal error formula is \frac{2S.D}{\sqrt{n} }

but if 'n' is sample size then n = \frac{1}{(margin error)^{2} }

Given margin error is 36% = 0.036

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<u>Step 2</u>:-

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after simplification, we get

\sqrt{p(1-p)} = \frac{1}{2}

squaring on both sides, we get

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multiply 'p' inside

p-p^{2} =\frac{1}{4}

cross multiplication '4' and simplify

4p^{2} -4p +1 =0 ........(1)

finding 'p' value

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(2p)^{2} -2(2p)(1)+1^{2} = (2p-1)^2

(2p-1)^2 =0

p=\frac{1}{2}

<u>conclusion</u>:-

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the sample proportion is p = \frac{1}{2}

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