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3 years ago

Simplify. √49 14 12 7 9

Mathematics

1 answer:

LiRa [457]3 years ago

8 0

Answer:

or -7

Step-by-step explanation:

sqrt(49)

What number multiplied by itself = 49

7*7 = 49

-7*-7 = 49

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An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio

Rudik [331]

Answer:

a) E(y) = 0.8

b) The average subcharge is $165

Step-by-step explanation:

We are given the following distribution in the question:

y: 0 1 2 3

P(y): 0.50 0.25 0.20 0.05

a) E(y)

$E(y) = \displaystyle\sum y_iP(y_i)\\\\E(y) = 0(0.50)+1(0.25)+2(0.20)+3(0.05)\\E(y) = 0.8$

b) Expected value of subcharge

Subcharge =

$\$110y^2$

Expected value of subcharge =

$=110E(y^2)\\\\=110\displaystyle\sum y_i^2P(y_i)\\\\=110(0^2(0.50)+1^2(0.25)+2^2(0.20)+3^2(0.05))\\=110(1.5)=165$

Thus, the average subcharge is $165

5 0

3 years ago

Josh has 4 times as many pears as leya, who has one half as many pears as amy. If josh has 32 pears how many does amy have?

arlik [135]

<h3>The number of pears Amy has is 16.</h3>

Step-by-step explanation:

Let J represent the number of pears Josh has.

Let L represent the number of pears Leya has.

Let A represent the number of pears Amy has.

From the question given above,

Josh (J) = 4 × Leya (L)

J = 4L ....... (1)

Leya (L) = ½ × Amy (A)

L = ½A ........ (2)

Next, we shall determine the number of pears Leya has. This can be obtained as follow:

From equation 1

J = 4L

But

Josh (J) = 32 pears

Thus,

32 = 4L

Divide both side by 4

L = 32 / 4

<h3>Leya (L) = 8 pears </h3>

Finally, we shall determine the number pears Amy has. This can be obtained as follow:

From equation 2

L = ½A

But

Leya (L) = 8 pears

Thus,

8 = ½A

Cross multiply

A = 8 × 2

<h3>Amy (A) = 16 pears </h3>

Therefore, Amy has 16 pears.

Learn more: brainly.com/question/20971657

6 0

3 years ago

Read 2 more answers

A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%

OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u> $(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$ <u></u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

$(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )$

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0

3 years ago

Quadrilateral STWR is inscribed inside a circle as shown below. Write a proof showing that angles T and R are supplementary.

AlladinOne [14]

Observe the given figure.

Here, angle T and R are the inscribed angles.

And sum of inscribed angles is half of measure of intercepted arcs.

Since, the measure of intercepted arcs is 360 degrees.

Therefore, $\angle T + \angle R = \frac{1}{2} \times 360 ^{\circ}$

$\angle T + \angle R = 180 ^{\circ}$

Hence, the sum of the two angles is 180 degrees.

Therefore, these are the supplementary angles.

Therefore, angle T and angle R are supplementary angles.

Hence, proved.

8 0

3 years ago

HELP PLEASEEEEE<br><br><br> Combine like terms to simplify the expression:<br> 1.17-0.07a+(-3.92a)

chubhunter [2.5K]

Answer: hope this helps

Step-by-step explanation:

Simplifying

1.17 + -0.07a + (-3.92a) = 0

Combine like terms: -0.07a + (-3.92a) = -3.99a

1.17 + -3.99a = 0

Solving

1.17 + -3.99a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1.17' to each side of the equation.

1.17 + -1.17 + -3.99a = 0 + -1.17

Combine like terms: 1.17 + -1.17 = 0.00

0.00 + -3.99a = 0 + -1.17

-3.99a = 0 + -1.17

Combine like terms: 0 + -1.17 = -1.17

-3.99a = -1.17

Divide each side by '-3.99'.

a = 0.2932330827

Simplifying

a = 0.2932330827

6 0

3 years ago