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3 years ago

Pppppppjnjk hieffhuie pleaase help

Mathematics

2 answers:

dsp733 years ago

7 0

Answer:

answer: 30 in sq

Hope that helps!

xxTIMURxx [149]3 years ago

6 0

Answer:

Step-by-step explanation:

I'm not sure if it's right but you can try it

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A bottle of medicine contained 300mL. Convert this to liters.

Readme [11.4K]

1 L = 1000 ml
So
to convert 300ml to liters
300/1000= 0.3

6 0

3 years ago

15. Geoff can mow an entire lawn of 450 square feet in 30 minutes. Assuming he mows at a constant rate, write the linear equatio

Ivahew [28]

Answer:

y=15x

Assuming he is mowing at a constant rate it would be 15 square feet per minute.

Step-by-step explanation:

7 0

3 years ago

Find the equation of thr line perpendicular to y= 3/2x+1 and passing through the point (5,1)

aliina [53]

Answer:

y=-2/3x+13/3

Step-by-step explanation:

5 0

4 years ago

I need help fast plz

Mrrafil [7]

Answer:

276.3 sq ft

Step-by-step explanation:

$2 \times \pi {4}^{2} + 2 \times 4 \times \pi \times 7 = 276.3$

4 0

3 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

3 years ago