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Tanya [424]
3 years ago
8

What is (-5/4) + 75/40 + 100% Please help and explain.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0
I think its 100.625... hope this helps :)
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students recorded the total number of pages and chapters in each of several books on the scatterplot. Based on the sbcatterplot,
Natalija [7]

Answer:

7

Step-by-step explanation:

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3 years ago
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A planet has a circular orbit around a star. It is a distance of 65,000,000 km from the centre of the star. It orbits at an aver
guapka [62]

Answer:

Step-by-step explanation:

Orbit = 2*pi * r

r = 65000000 km

Orbit = 65000000 * 2 * 3.14

Orbit = 406 200 000             km

d = 406 200 000

s = speed = 65000 km / hr

t = time = d / s

t = 406,000,000 / 65000

t = 6280 hours.

1 day = 24 hours.

t = 6280 / 24 = 261.67 days

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3 years ago
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crimeas [40]
# 3 is .4 because u multiply .2*.2
4 0
4 years ago
The amount of an invoice is $1000, with terms 2/10, n45. The amount to be paid within the discount period is:
just olya [345]

Answer:The amount to be paid within the discount period is $980

Step-by-step explanation:

The term 2/10, n45

means that 2%  discount is  offered if the amount of invoice is paid within 10 days from the date of invoice .

n/45 means that the buyer will pay the full amount within 45 days if he /she does not pay within the discount period of 10 days .

Now if the amount is to be paid within the discount period, the amount will be

Amount to be paid= $1000- 2% of 1000

= $1000-20

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6 0
3 years ago
A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of flyers to six people. With
Mandarinka [93]

Answer:

In summation form \sum_{n = 1} ^{5} 6(6)^{n - 1}

Step-by-step explanation:

Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.

So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by

6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).

So, in summation form \sum_{n = 1} ^{5} 6(6)^{n - 1}

Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)

3 0
3 years ago
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