Whoever answers first I will give the name the Brainliest.!

Mathematics

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer:

43,200

Step-by-step explanation:

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Help again and thanks..........

LenKa [72]

Answer:

a = $8
s = $5

Step-by-step explanation:

When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to

ax +by = c
dx +ey = f

are ...

∆ = bd -ea
x = (bf -ec)/∆
y = (cd -fa)/∆

Using that rule here, we find ...

∆ = 5·3 -6·2 = 3

a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8

s = (41·3 -54·2)/3 = 41 -18·2 = 5

This math can be performed in your head, which is the intent of formulating the rule in this way.

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Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.

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Comment on the question

We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.

6 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$