If you factor the expression of part A, you will get the expression of part B
the reason is that the perimeter of a rectangle is equal to 2(l+w)
so in the factorization number 2 will be multiplied by the rest of the expression
good luck
Answer:
y=6x+5
Step-by-step explanation:
I am not sure if this is the answer but it's worth a try...
Answer:
C. √2 - 1
Step-by-step explanation:
If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)
Let r = the radius of the small circle
Using Pythagoras' Theorem 
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
to find the diagonal of the square:
So the diagonal of the square = 
We are told that the radius of the large circle is 1:
⇒ Diagonal of square + r = 1
Using the quadratic formula to calculate r:
As distance is positive, 
only
Answer: y=-(1/8)x+(21/2)
Explanation:
The new equation’s slope needs to be perpendicular to y=8x-1
To get the new slope, we take the negative reciprocal of the slope from above
8 —> -1/8
Now we have y=-(1/8)x+b but it needs to pass through (4,10), so we need to find the value of b that makes this possible.
Since (4,10) is in the form of (x,y) we can plug in these values into the new equation to solve for b:
y=-(1/8)x+b
10=-(1/8)4+b
10=(-1/2)+b
b=(21/2)
Now put b back into the new equation
y=-(1/8)x+b
y=-(1/8)x+(21/2)
Answer:
(3, 50) and (14,303)
Step-by-step explanation:
Given the system of equations;
y=23x–19 ....1
x²–y= – 6x–23 ...2
Substitute 1 into 2;
x²–(23x-19)= – 6x–23
x²–23x+19= – 6x–23 .
x²-23x + 6x + 19 + 23 = 0
x² - 17x + 42 = 0
Factorize;
x² - 14x - 3x + 42 = 0
x(x-14)-3(x-14) = 0
(x-3)(x-14) = 0
x = 3 and 14
If x = 3
y = 23(3) - 19
y = 69-19
y = 50
If x = 14
y = 23(14) - 19
y = 322-19
y = 303
Hence the coordinate solutions are (3, 50) and (14,303)
