Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Answer:
10 i think
Step-by-step explanation:
Answer:
(x,y,z)=( -2, -1 ,5)
Step-by-step explanation:
9x+2y-27z=-155 (1)
-11x-y+37z=208 (2)
19x+6y-52z=-304 (3)
(1) *3 ;(2) *6 ;(3)*1, you have
27x+6y-81z=-465 (1)
-66x-6y+222z=1248 (2)
19z+6y-52z=-304 (3)
(1) +(2), you have
-39x+141z= 783 (4)
(4) /3, you have
-13x +47z=261 (4)
(2) +(3), you have
-47x+170z=944 (5)
From ( 4) and (5), you have equations
-13x +47z=261 (4)
-47x+170z=944 (5)
(4)*(-47); (5)*13, you have
611x-2209z=-12,267 (4)
-611x+2210z=12,272 (5)
(4)+(5), you have
z=5
Replace z=5 in (4), you have
611x- 2209*5=-12,267
611x- 11,045 =-12,267
611x=-1222
x= -2
Replace x=-2, z=5 in (1) , you have
9*(-2) +2y -27*5=-155
-18+2y-135=-155
-18+2y=-20
2y=-2
y=-1
Result (x,y,z)=( -2, -1 ,5)
Answer:
22.68 or 22.7
Step-by-step explanation:
hope this helps
If one Angle is = 30
And the other two angles are equal
Given: x = l
ATQ
⇒30+x+l= 180
⇒x + x = 180-30
⇒2x = 150
⇒x = 150/2
⇒x = 75
Therefore x = 75
And the angles are 30, 75 and 75
Must click thanks and mark brainliest
