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pochemuha
2 years ago
15

-9.2 + 4.4= -81.4 + (-12)=

Mathematics
2 answers:
Darina [25.2K]2 years ago
7 0

Answer:

-9.2 + 4.4 = -4.8

-81.4 + (-12) = -93.4.

artcher [175]2 years ago
4 0
-9.2+4.4=-4.8
-81.4+(-12)=-93.4
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What is the equation in slope intercept form for (2,5) (3,12)
kondaur [170]

Slope formula: y2-y1/x2-x1

= 12-5/3-2

= 7/1

= 7

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7 0
3 years ago
2/9 ,3/9 and 4/9 change them into decimals plzz help
slavikrds [6]
2/9 = 0.2222 or 0.22
3/9 = 0.3333 or 0.33
4/9 = 0.4444 or 0.44
7 0
3 years ago
Read 2 more answers
Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
( 2 7/8 + 3 3/8 ) + 1 1/8 =​
Monica [59]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
Over the course of a multi-stage 4510-km bicycle race, the front wheel of an athlete's bicycle makes 1.70x106 revolutions. How m
iragen [17]

Answer:

The wheel have made 2.10 * 10^{6}  m revolutions.

Step-by-step explanation:

The total distance traveled during the race is

D = 4510km [(1000m)/(1km)] = 4510 * 10^{3} m

The radius (r1) of the smaller bicycle wheel is

r1 = \frac{D}{2*pi*N1} = \frac{4510 * 10^{3} m }{2*pi*(2.18*10^{6}) } =0.329 m

Than the larger wheel has a radius

r2 = 0.329 m + 0.012 m = 0.341 m

Over the same distance this wheel would make N2 revolutions

N2 = \frac{D}{2*pi*r2} = \frac{4510 * 10^{3} m }{2*pi*(0.341) } = 2.10 * 10^{6}  m

8 0
3 years ago
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