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igomit [66]
3 years ago
5

Thx and have a great day!!

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:A

Step-by-step explanation:<3and <11 are corresponding angles, and corresponding angles are congruent

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PLEASE SOMEONE HELP ME ON THIS ! 30 points
Mrrafil [7]
Equaton of a circle that is centerd at (h,k) and radius r is

(x-h)²+(y-k)²=r²

center is (-4,9) and radius is 11

(x-(-4))²+(y-9)²=11^2
(x+4)²+(y-9)²=121
4 0
3 years ago
Please help!!! urgent
Crank

Answer:

E

Step-by-step explanation:

is the answer

5 0
3 years ago
Which of the following are properties of a perfect square trinomial? Select all that apply.. A.Neither of the perfect squares ca
aliya0001 [1]
Definition 1: Perfect squares are numbers or expressions that are the product of a number or expression multiplied to itself (7 times 7 is 49, so 49 is a perfect square).

Definition 2: <span>Binomials are algrebraic expressions containing only two terms.</span><span />
<span>
</span><span>Definition 3: Trinomials are algebraic expressions that contain three terms. </span><span />

Perfect square trinomials are algebraic expressions with three terms that are created by multiplying a binomial to itself. There are two formulas for perfect square trinomials:
(a+b)^2=a^2+2ab+b^2, \\ (a-b)^2=a^2-2ab+b^2.
From these formulas you can see that:
A. <span>"Neither of the perfect squares can have a minus sign" is true statement;
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B. "<span>The first and third terms must be perfect squares" is true statement;
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C. "<span>If the perfect square terms are a^2 and b^2 then the other term must be (ab)^2" is false statement;
</span>
D. "<span>None of the above is a property of a perfect square trinomial" is consequently false statement.
</span>






3 0
3 years ago
Read 2 more answers
(a^2-b)^3
Ganezh [65]
-1 is correct answer because
a= -2
b= 5 then
(-2^2-5)^3
(4-5)^3
(-1)^3
-1
7 0
3 years ago
Evaluate the expression 4b-6d if b = 7 and d=3
viktelen [127]

Answer:

<em>1</em><em>0</em>

Step-by-step explanation:

4*7 - 6*3

\/ \/

28 - 18

\ /

= 10

3 0
3 years ago
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