Find (a) the slope of the curve at the given point p, and (b) an equation of the tangent line at p. y=−2−9x2; p(2,−38)
1 answer:
Answer:
a) -36
b) y = -36x +34
Step-by-step explanation:
a) The slope is found using the derivative of the function.
f'(x) = dy/dx = 0 -9(2x) = -18x
Then at x=2, the slope is ...
f'(2) = -18·2 = -36
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b) The point-slope form of the equation can be written as ...
y = -36(x -2) -38
Simplifying to slope-intercept form, we get ...
y = -36x +34
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