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frozen [14]
3 years ago
12

identify the transformations that map rectangle A to rectangle A'. A) reflect over y-axis, reflect over line y = 5, then 3 units

left Eliminate B) reflect over x-axis, reflect over line y = 5, then 3 units left C) reflect over x-axis, reflect over line y = 5, then 3 units right D) reflect over y-axis, reflect over line y = 5, then 3 units right
Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:7:8

Step-by-step explanation:answer

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9x^2+16=0 what are the solutions
seraphim [82]
X=4i/3,-4i/3

Need 20 characters
8 0
3 years ago
I need to know if a is right and answers to b and c
xxTIMURxx [149]

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Your answer is A. my Good sir

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Step-by-step explanation:

3 0
2 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
aev [14]

Answer:

P(X < 3) = 0.7443

Step-by-step explanation:

We are given that the random variable X has a binomial distribution with the given probability of obtaining a success. Also, given n = 6, p = 0.3.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 6

            r = number of success = less than 3

           p = probability of success which in our question is 0.3.

LET X = a random variable

So, it means X ~ Binom(n=6, p=0.3)

Now, Probability that X is less than 3 = P(X < 3)

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

             = \binom{6}{0}0.3^{0} (1-0.3)^{6-0}+ \binom{6}{1}0.3^{1} (1-0.3)^{6-1}+ \binom{6}{2}0.3^{2} (1-0.3)^{6-2}

             = 1 \times 1 \times 0.7^{6}  +6 \times 0.3^{1}  \times 0.7^{5}  +15 \times 0.3^{2}  \times 0.7^{4}

             = 0.11765 + 0.30253 + 0.32414 = 0.7443

Therefore, P(X < 3) = 0.7443.

5 0
3 years ago
What is the square root of 255683
ss7ja [257]

Answer:

505.651065

Step-by-step explanation:

It will basically be converted into a decimal.

6 0
3 years ago
Im pulling my hair out with this problem my calculator simplified it to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%2B%2F-%5Cs
Tamiku [17]

~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -\frac{5}{3} \end{cases}

6 0
1 year ago
Read 2 more answers
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