Yes, you're correct, it's the first one. He should do research before he does an experiment, because someone else may already know.
Answer:
Explanation:
They are both protects what enters the cell or exit out the cell
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
Answer:
Autotrophs, but not heterotrophs, can nourish themselves beginning with and other nutrients that are inorganic.
Explanation:
Unlike heterotrophs, autotrophs such as green plants, are able to synthesize their food (in form of sugar molecules) starting with inorganic molecules like atmospheric carbon dioxide, water in the presence of sunlight.
This is commonly known as photosynthesis. The equation is shown below
6CO2 + 6H2O --> C6H12O6 + 6O2 + Energy
C. pass those traits on to future generations
