Identify the number that does not belong with the other three. Explain your reasoning.

Mathematics

1 answer:

mojhsa [17]3 years ago

6 0

Answer:

To identify which integer does not belong with the rest, we must first evaluate each.

Step-by-step explanation:

[25.6...] is already evaluated. Therefore, let's move on to Integer <em>b: </em> $\sqrt{x}$ , where is <em>x </em>is 48.

48 = 2 * 24--> 2 * 12--> 2 * 6--> 2 * 3

√48 = $\sqrt{2}$ * 2 * 2 * 2 * 3

We have 1 perfect sqaure: $\sqrt{2}$ * 2

When we multiply, we receive 2.

Therefore, 2 * $\sqrt{2 * 3}$

When -51/2 is relatively prime, we receive -25 1/2

Finally, the last integer is already simplified.

Based on these results, you may determine the number that does not belong with the other three, whether than is through means of irrationability, value, absolte value, or whatever other means you decide.

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Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then