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Gekata [30.6K]
3 years ago
6

How do you solve for x in x^2+5x=36

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0

Answer: (-9,4)

Step-by-step explanation: First, we set the equation equal to zero by subtracting 36 from both sides to get x² + 5x - 36 = 0.

Next, we factor the left side of the equation

as the product of two binomials.

Since the factors of -36 that add to +5 are +9 and -4,

we have (x + 9)(x - 4) = 0.

This means that either x + 9 = 0 or x - 4 = 0.

Solving each equation from here,

we have x = -9 or x = +4.

So your solution set is (-9,4).

Vlad [161]3 years ago
7 0
First we want to set the equation equal to zero by subtracting 36 from each side...

x^2 + 5x -36 = 0

Now we factor

(x + 9)(x - 4) = 0

Now set each expression equal to zero and solve...

x + 9 = 0              x - 4 = 0
x = -9                    x = 4

Your solution set is

(-9, 4)
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| x - 1 | = 5x + 10<br> Check for extraneous solutions.
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[x-1]=5x+10

We have two equations:
1) x-1=5x+10

x-1=5x+10
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2) x-1=-(5x+10)

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we check it out:
1) x=-11/4
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[-3/2  - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2  + 10
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5/2=5/2; this solution works.

Therefore:

Answer: x=-3/2.
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