Answer and explanation:
Farmer's number of apples = 96 apples
Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag
And also all apples in each bag are equal
We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder
4 can divide 96= 24
5 cannot divide 96 without remainder
6 can divide 96 =16
7 cannot divide 96 without remainder
8 can divide 96=12
9 cannot divide 96 without remainder
10 cannot divide 96 without remainder
From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10
4 apples = 24 bags
6 apples = 16 bags
8 apples = 12 bags
Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples
Answer:
A
Step-by-step explanation:
This isn't an equation because there is no = sign so we can eliminate B and C. Since this has variables in it it's algebraic so the answer is A.
Answer:
(-162)/7 or -23 1/7 as mixed fraction
Step-by-step explanation:
Simplify the following:
(-36)/14 (-18) (-3)/6
Hint: | Express (-36)/14 (-18) (-3)/6 as a single fraction.
(-36)/14 (-18) (-3)/6 = (-36 (-18) (-3))/(14×6):
(-36 (-18) (-3))/(14×6)
Hint: | In (-36 (-18) (-3))/(14×6), divide -18 in the numerator by 6 in the denominator.
(-18)/6 = (6 (-3))/6 = -3:
(-36-3 (-3))/14
Hint: | In (-36 (-3) (-3))/14, the numbers -36 in the numerator and 14 in the denominator have gcd greater than one.
The gcd of -36 and 14 is 2, so (-36 (-3) (-3))/14 = ((2 (-18)) (-3) (-3))/(2×7) = 2/2×(-18 (-3) (-3))/7 = (-18 (-3) (-3))/7:
(-18 (-3) (-3))/7
Hint: | Multiply -18 and -3 together.
-18 (-3) = 54:
(54 (-3))/7
Hint: | Multiply 54 and -3 together.
54 (-3) = -162:
Answer: (-162)/7
10,000 x .10 = $1000
22500-10000=12500 x .12 = $1500
$1000 + $1500 = $2500
Answer:
a = -3 b = -5 c = 9
Step-by-step explanation:
A quadratic function is written in the form
ax^2 +bx +c =0
-3x^2-5x+9=0
a = -3 b = -5 c = 9
