All categories

3 years ago

Khan academy use Pythagorean theorem to find isosceles triangle size length

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

Answer:

I know

Step-by-step explanation:

You might be interested in

Jerry is saving his money. He started with $15.00. If he adds $10.00 to his savings

posledela

Answer:

$40

Step-by-step explanation:

use y = mx + b

y = amount saved = ?

m = amount saved per week = $10

x = time (in months) saving = 2.5

b = money jerry started with = $15

plug in:

y = (10)(2.5)+15

y = $40

6 0

3 years ago

WHAT WOULD THIS BEEE

Neporo4naja [7]

No, the angles are roughly 34, 44, and 102

5 0

3 years ago

Sabra joins a cooking club for $8.50 and pays $6.25 each month. She also joins a movie club for $12 and pays $3.75 each month. W

STatiana [176]

Answer: The simplified express is 10m + 20.5 where m represents the total number of months.

To start we can write the following two expressions for her expenses.
8.5 + 62.5m and 12 + 3.75m

Then, adding the two expressions together will give us a combined expression of: 10m + 20.5

8 0

3 years ago

Write an equation for: The length of a rectangle is 6 times the width. use the variables l and w

Fittoniya [83]

L=6w would be an equation for the length of a rectangle that is 6 times the width

8 0

4 years ago

Need help with this....

Yakvenalex [24]

Answer:

$\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}$

Step-by-step explanation:

$f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}$

$=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2$

6 0

3 years ago