All categories

3 years ago

In solving the equation 2x+5=9, which property of equality do we use first? Why?

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

Property of Addition. sorry if i’m wrong

You might be interested in

The students in the fourth grade sold 684 erasers for a fund-raiser. They sold 4 times as many erasers as the students in fifth

Delicious77 [7]

4 graders sold 4 times as many erasers as the students in fifth grade
so
684 / 4 = 171

answer
students in 5 grade sold 171 erasers

4 0

3 years ago

The product of eight and a number decreased by four is the same as eight plus five time the same number.

dedylja [7]

Answer:

The Answer is: The Number is 4

Step-by-step explanation:

Let n = the number.

Eight times a number minus 4 equals 8 plus 5 times the number.

8n - 4 = 8 + 5n

3n = 12

n = 4, the number is 4.

Proof:

8(4) - 4 = 8 + 5(4)

32 - 4 = 8 + 20

28 = 28

Hope this helps! Have an Awesome Day!! :-)

5 0

4 years ago

The manager at Gabriela's Furniture Store is trying to figure out how much to charge for a book shelf that just arrived. The boo

tatuchka [14]

Answer:

Step-by-step explanation:

The book shelf arrived at the wholesale price = $ 147

Mark up on the furniture = 60 %

So The Cost Price = $147

Markup = 60% = 0.60

So using the formula

Sale Price = Cost Price + Cost Price * Markup percentage

Sale Price = 147 + 147*(0.60)

Sale Price = $ 235.20

3 0

4 years ago

Read 2 more answers

likoan [24]

Answer:

1/4

Step-by-step explanation:

add the ratios

3+5=8

240 Divided by 8=30

3x30=90

5x30=150

Ann(90)

Bob150)

90/2=45 (remeber Ann gave half)

150/10=15 (remeber Bob gave a tenth)

45+15=60 (Colin received this amount)

60/240=1/4

8 0

4 years ago

Rewrite the function by completing the square. 4x^2-4x+1=0

andrey2020 [161]

Do in completing the square method.

${4x}^{2} - 4x + 1 = 0 \\ 4x^{2}-4x=-1 \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4} \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4} \\ x^{2}-x=\frac{-1}{4} \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2} \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4} \\ x^{2}-x+\frac{1}{4}=0 \\ \left(x-\frac{1}{2}\right)^{2}=0 \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}$

Now simplify.

$x-\frac{1}{2}=0 \\ x-\frac{1}{2}=0 \\ \\ \rightarrow \: x=\frac{1}{2} \\ \rightarrow \: x=\frac{1}{2}$

So, answer is..

$\boxed{x=\frac{1}{2} }$

Now rewrite the equation.

$4 x ^ { 2 } - 4 x + 1 = 0 \\ \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 }$

Verification :-

$4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-\frac{4}{2}+1=0 \\ 1-2+1=0 \\ -1+1=0 \\ \underline{ 0 = 0} \: \\ \dashrightarrow \text{true}$

3 0

3 years ago