Answer:
The mean is 2.75.
The margin of error is 0.62.
Step-by-step explanation:
In this case, we know the 95% confidence interval, and we want to know the mean and the margin of error.
The mean can be calculated as the average between the upper limit and lower limit:
The margin of error is the difference between the upper (or lower limit) and the mean. It equals the product between the z-value and the standard deviation divided by the square of the sample size.
It can also be calculated as half the difference of the limits of the confidence interval.
We only have the limits of the confidence interval to calculate the margin of error:
15. 29.95 x 36 = 1078.2, and to look appropriate $1,078.20
16. This one is just finding a equal fraction that's a simplifed version of this one. 24 / 32 = 3 / 4. I divided both sides by eight.
Answer:
The set of all pages in the book:
S={1, 2, 3, ..., 428}
Step-by-step explanation:
The sample space is the set containing all possible outcomes for the experiment. In this problem, the experiment is stopping at a random page of the textbook, and the sample space is the set of all pages in the book:
S={1, 2, 3, ..., 428}.
Answer:
P-value = 0.009997
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 24
Nature of test: One-tailed test(Left tailed test)
We have to calculate the p-value.
Degree of freedom = n - 1 = 23
We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.
P-value = 0.009997
0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.
1/3x + 5 = -2 is the way to set up the equation…. You got this!
