Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
What’s the question asking?
Answer:
187
Step-by-step explanation:
a=12,d=17-12=5
nth term =a+(n-1)d
36th term=12+(36-1)5
=12+(35×5)
12+175
36th term=187
Can u show me an example so I could do this foru
Answer:
Answer is <em>n</em><em>/</em><em>2</em>
Step-by-step explanation:
I started with the constant n
In second step I divided the n by 2
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS</em><em> </em><em>FOR GIVING ME THE OPPORTUNITY TO</em><em> </em><em>ANSWER YOUR QUESTION</em><em>. </em>
