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2 years ago

Jada's pet turtle walked 12 feet, and then that length again.

Mathematics

1 answer:

ioda2 years ago

7 0

Answer:

if you are asking in all how many feet he walked the 24ft

Step-by-step explanation:

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Ben has 1/2 of a loaf of bread if he and his 3 friends share the 1/2 loaf equally how much of the whole loaf does each person ge

Dvinal [7]

Given:
1/2 loaf of bread
3 friends

1/2 ÷ 3 ⇒ 1/2 * 1/3 = 1*1 / 2*3 = 1/6

In dividing fractions, get the reciprocal of the divisor and multiply it to the dividend

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3 years ago

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melissa can earn $18 each time she cuts grass. if she cuts the grass x times, write an expression that shows how much she will e

Alborosie

18x

Simple as that. 18 times however many times she cuts the grass

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2 years ago

Your sister is considering the purchase of a home rather than renewing the lease on her

notka56 [123]

Answer:

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b. What mortgage amount can she borrow? $ 120,000

Step-by-step explanation:

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2 years ago

(Help please) A transformation was performed on oval A as shown in the graph. What type of transformation was performed? Does th

labwork [276]

Answer: B. Translation, yes

-A is incorrect because the shape did not change
-C is incorrect because the shape isn’t reflected over the y axis
-D is incorrect because it’s clearly moved to a completely different part of the grid

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2 years ago

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Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

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1 year ago