Question

Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0

Answer 1

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

$h(x) = -\frac{1}{3}x^2 + 4$ --- $x \ne 2$

$h(x) = -4$ --- $x= 2$

Required

$h(-5)\ \&\ h(2)$

Calculating h(-5)

This implies that: x = -5

$-5 \ne 2$

So, we make use of:

$h(x) = -\frac{1}{3}x^2 + 4$

Substitute -5 for x

$h(-5) = -\frac{1}{3} * (-5)^2 + 4$

$h(-5) = -\frac{1}{3} * 25 + 4$

$h(-5) = -\frac{25}{3} + 4$

Take LCM

$h(-5) = \frac{-25+12}{3}$

$h(-5) = -\frac{13}{3}$

Calculating h(2)

This implies that: x = 2

$2 = 2$

So, we make use of:

$h(x) = -4$

Substitute 2 for x

$h(2) = -4$

Use the above explanation to answer your question