5+3+-9+3=2 and then the varibles so the answer is 2 cubed
Answer:
We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .
3 even: 1 odd..................................
Answer:
D
Step-by-step explanation:
A)
3(2) + 4(-2) = -2 2(2)-4(-2) = -8
6 - 8 = -2 4 + 8 = -8
Correct Incorrect
B)
3(6) + 4(-5) = -2 2(6) - 4(-5) = -8
18 - 20 = -2 12 + 20 = -8
Correct incorrect
C)
3(4) + 4(4) = -2
12 + 8 = -2
incorrect
D)
3(-2) + 4(1) =-2 2(-2) - 4(1) = -8
-6 + 4 = -2 -4 - 4 = -8
Correct Correct
Best way is process of elimination
<span>I get 0.26% for part A and 75% for part B. My work is in the attached document.</span>
