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Yuliya22 [10]
3 years ago
14

Please help me I really don't understand

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0

Answer:

Step-by-step explanation:

goblinko [34]3 years ago
5 0
The answer to the problem is 255
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Problem in the picture
STatiana [176]

Answer:

B)

Step-by-step explanation:

65 x 2.5 = 162.5

70 x 1.5 = 105

162.5+105=267.5

7 0
3 years ago
Read 2 more answers
X^2 + 1/4 or 7 or 7/2 x + 49
wolverine [178]

Answer:

14

Step-by-step explanation:

Squaring a number (a+b) for example is a^2+2ab+b^2. So you square root x^2 and 49, you get x and seven respectively. you multiply them together and on top of that multiply the product by 2. so 7x*2 is 14x and ye

7 0
3 years ago
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Please answer quick as possible ​
Murrr4er [49]

Answer:

The correct option is B

i just answer that on our test and i got A+

<h3 />
7 0
2 years ago
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If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
There are 4 consecutive integers that sum to 394. What is the least of these integers?​
Ostrovityanka [42]

Answer:97

Step-by-step explanation:

the average of the four integers is 394/4 = 98.5. So the four consecutive integers with a sum of 394 are the two integers closest to 98.5 and on each side of 98.5: 97, 98, 99, and 100.

3 0
3 years ago
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