If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.
We are required to find the approximate margin of error.
Margin of error is the difference between calculated values and real values.
n=1488
p=0.69
Margin of error=z*![\sqrt{p(1-p)/n}](https://tex.z-dn.net/?f=%5Csqrt%7Bp%281-p%29%2Fn%7D)
Z score when confidence level is 99%=2.576.
Margin of error=2.576*![\sqrt{0.69(1-0.69)/1488}](https://tex.z-dn.net/?f=%5Csqrt%7B0.69%281-0.69%29%2F1488%7D)
=2.576*![\sqrt{(0.69*0.31)/1488}](https://tex.z-dn.net/?f=%5Csqrt%7B%280.69%2A0.31%29%2F1488%7D)
=2.576*![\sqrt{0.2139/1488}](https://tex.z-dn.net/?f=%5Csqrt%7B0.2139%2F1488%7D)
=2.576*![\sqrt{0.0001437}](https://tex.z-dn.net/?f=%5Csqrt%7B0.0001437%7D)
=2.576*0.01198
=0.03088
Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Learn more about margin of error at brainly.com/question/10218601
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Answer:
6.68754...
Step-by-step explanation:
Assuming you mean:
![\sqrt{2}\cdot 3^{\sqrt{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%5Ccdot%203%5E%7B%5Csqrt%7B2%7D%7D)
Answer:
false
Step-by-step explanation:
Because it multiplying by 2's but 13x2=26 but it says 24 so that why it is false
Answer:
.
Step-by-step explanation:
We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.
We will use volume formula of sphere to solve our given problem.
, where r is radius of sphere.
The difference of volumes would be volume of larger sphere minus volume of smaller sphere.
![\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3](https://tex.z-dn.net/?f=%5Ctext%7BDifference%20of%20volumes%7D%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%28%5Ctext%7B8%20cm%7D%29%5E3-%5Cfrac%7B4%7D%7B3%7D%5Cpi%28%5Ctext%7B2%20cm%7D%29%5E3)
![\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3](https://tex.z-dn.net/?f=%5Ctext%7BDifference%20of%20volumes%7D%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%28512%29%5Ctext%7B%20cm%7D%5E3-%5Cfrac%7B4%7D%7B3%7D%5Cpi%288%29%5Ctext%7B%20cm%7D%5E3)
![\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3](https://tex.z-dn.net/?f=%5Ctext%7BDifference%20of%20volumes%7D%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%28512-8%29%5Ctext%7B%20cm%7D%5E3)
![\text{Difference of volumes}=4\pi(168)\text{ cm}^3](https://tex.z-dn.net/?f=%5Ctext%7BDifference%20of%20volumes%7D%3D4%5Cpi%28168%29%5Ctext%7B%20cm%7D%5E3)
![\text{Difference of volumes}=672\pi\text{ cm}^3](https://tex.z-dn.net/?f=%5Ctext%7BDifference%20of%20volumes%7D%3D672%5Cpi%5Ctext%7B%20cm%7D%5E3)
Therefore, the difference between volumes of the spheres is
.
B pretty sure that it’s that