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Oliga [24]
3 years ago
5

The number of bacteria in a Petri dish increases by 18% every hour. If there were initially 200 bacteria placed in the Petri dis

h, which function can be used to determine the number of bacteria in the Petri dish in exactly x hours?

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

an exponential equation has the form y=ar^x where y=final amount, a=initial amount, r=rate, and x=time, in this case

y=200(1.18)^x

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2 years ago
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Paula, the local baker, usually makes 1"5 loaves of bread and 10 cakes per day, but today she made 25 loaves of bread and 12 cak
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Answer:

the percentage increase for bread and cake is 66.67% and 20% respectively  

Step-by-step explanation:

The computation of the percentage increase for each bakery item is shown below:

For bread

= (25  - 15) ÷ 15

= 66.67%

For cakes

= (12 - 10) ÷ (10)

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Hence, the percentage increase for bread and cake is 66.67% and 20% respectively  

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What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)
olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.  

For example:

Type of change               Effect on y = f(x)

y = f(x - c)                      horizontal shift: c units to right

So

Considering the function

f(x) = x^2

The graph is shown below. The first figure is representing f(x) = x^2.

Now, considering the function

\:f\left(x\right)=\left(x-6\right)^2

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of \:f\left(x-6\right)=\left(x-6\right)^2 is shown below in second figure. It is clear that the graph of  \:f\left(x-6\right)=\left(x-6\right)^2  is shifted 6 units to the right as compare to the function f(x) = x^2.

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

5 0
3 years ago
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