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sammy [17]
3 years ago
5

Determine whether each number is a solution of the

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0

Answer:

No

Step-by-step explanation:

1. 4(-2)+2<-6

2. -8+2<-6

3. -6<-6

Hope this helps!!

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Hi!! can someone help me PLEASE? and DON'T BE AN IP ADDRESS TRACKER!!!!!!!
Artist 52 [7]

Answer:

47,759

Step-by-step explanation:

77+216 x 326 divided by 2

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3 years ago
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8/5÷3=______<br>Answer in a fraction form <br><br>PLZ HELP ME​
faltersainse [42]
8/5 divided by 3 in fraction form is 8/15
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GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out
Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area=length\times width

Area of garden and the walkway together is

Area=(14+2x)\times (10+2x)

396=140+28x+20x+4x^2

396=140+48x+4x^2

396=4(35+12x+x^2)

Divide both sides by 4.

99=35+12x+x^2

0=35-99+12x+x^2

0=-64+12x+x^2

Splitting the middle term, we get

x^2+16x-4x-64=0

x(x+16)-4(x+16)=0

(x+16)(x-4)=0

Using zero product property, we get

(x+16)=0\text{ and }(x-4)=0

x=-16\text{ and }x=4

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0
3 years ago
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Which of the following may fall outside a triangle? Check all that apply.?
Luda [366]
Circumcenter is the one among the following choices given in the question that may fall outside a triangle. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer you were looking for and it has come to your help.
5 0
3 years ago
In triangle ABC, a = 9, c = 5, and B = 120°. Find b2.
anygoal [31]

Answer:

(D) b^2=151

Step-by-step explanation:

Given: In triangle ABC, a=9, c=5 and ∠B=120°.

To find: The value of b^2.

solution: It is given that In triangle ABC, a=9, c=5 and ∠B=120°.

Now, using the law of cosines, we get

b^2=a^2+c^2-2(a)(c)cosB

Substituting the given values, we get

b^2=9^2+5^2-2(9)(5)cosB

b^2=81+25-90(\frac{-1}{2})

b^2=81+25+45

b^2=151

which is the required value of b^2.

Therefore, option D is correct.

3 0
3 years ago
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