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Tamiku [17]
3 years ago
8

A large mixing tank currently contains 225 225 gallons of water, into which 5 5 pounds of sugar have been mixed. A tap will open

, pouring 20 20 gallons of water per minute into the tank at the same time sugar is poured into the tank at a rate of 4 4 pounds per minute. Find the concentration (pounder per gallon) of sugar in the tank after t t minutes.
Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer: Hello mate!

you put every number twice, I will consider that in this problem we have:

225 gallons of water initial with 5 pounds of sugar. then each minute you add 20 gallons of water and 4 pounds of sugar.

the concentration is defined as pounds of sugar divided by the gallons of water. The gallons of water are 225 initially and 20 per minute, this is written as 225 + 20tt, where t is the minutes. The pounds of sugar is 5 + 4 per minute, then this can be written as 5 + 4t

C(t) = \frac{5 + 4t}{225 + 20t}

this is the equation that describes the concentration in pounder per gallon after t minutes.

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3(5s + 2)

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4 years ago
A submarine descends 45 1/2 feet from the ocean surface, clinbs 39 ft, and then descends an additional 18 3/4 ft. What must the
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decedns 18 and 3/4
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7 0
3 years ago
each year francesca earns a salary of 2% higher than her previous years salary. In her first 5 years at this job, she earned a t
Luda [366]

Answer:

$36,027.9

Step-by-step explanation:

Lets say her salary in the first year is s1. So, in the second year her salary will be 2% higher than x, this is, s1 + s1*0.02, so:

s2 = s1 + 0.02s1 = 1.02s1

Then in year 3 it will be s2 plus a 0.02 increase:

s3 = s2 + 0.02s2 = 1.02(s2) = 1.02 (1.02 s1) = 1.02^2(s1)

Then the same for s4: s3 salary plus the increase.

s4 = s3 + 0.02s3 = 1.02(s3) = 1.02 (1.02 s2) = 1.02(1.02*1.02 s1) =1.02^3(s1)

Finally for the 5th monts:

s5 = 1.02(s4) = 1.02^4(s1)

We know that s1+s2+s3+s4+s5 = 187,345

Lets replace all the salaries by its value depending on s1

s1 + 1.02s1 + 1.02^2(s1) + 1.02^3(s1) + 1.02^4(s1) = 187,345

We can add to the first term a s1^0 as it is eqaul to 1

s1 + 1.02s1 + 1.02^2(s1) + 1.02^3(s1) + 1.02^4(s1) = 187,345

Lets get 1s1 out as common factor:

s1 (1 + 1.02^1 + 1.02^2 + 1.02^3 + 1.02^4) = 187,345

s1 *5.20 = 187,345

Divide both sides by 5.20

s1 = 36,027.9

So, her salary in the 1st month was approximately $36,027.9

4 0
3 years ago
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