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3 years ago

HELP PLS. Due in 10 mins

Mathematics

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

1. Linear

2. Not Linear

3. Linear

4. Linear

Step-by-step explanation:

Function 1

Linear, follow a sequence of 4, 3

Function 2

Not Linear, does not follow a sequence

Function 3

Linear, follow a sequence of 1, 0

Function 4

Linear, follow a sequence of 3, -1

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Evaluate Cot0 if sin0= square root of 6/5

Lina20 [59]

To evaluate cot θ given that sinθ=√6/5 we shall have:
sin θ=opposite/hypotenuse
hence
opposite=√6
hypotenuse=5
thus the adjacent will be found using the Pythagorean theorem
c²=a²+b²
plugging in the value we get:
5²=(√6)²+b²
b²=25-6
b²=19
b=√19
thus
adjacent=√19
but
cotθ=1/tanθ
tanθ=√6/√19
hence:
cotθ=√19/√6

6 0

3 years ago

A cylinder has diameter of 4ft and a height of 9ft. Explain whether halving the diameter has the same effect on the surface area

elena55 [62]

Answer:

See Below

Step-by-step explanation:

The surface area of cylinder is given by the formula:

$SA=2\pi r^2 + 2\pi r h$

Where

r is radius ( diameter is 4, so radius is 4/2 = 2)

h is height ( h = 9)

Lets find original surface are:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (9)\\SA=8\pi +36\pi\\SA=44\pi$

Halving diameter:

diameter would be 4/2 = 2, so radius would be 2/2 = 1

So, SA would be:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (1)^2 + 2\pi (1) (9)\\SA=2\pi +18\pi\\SA=20\pi$

Halving height:

Height is 9, halving would make it 9/2 = 4.5

Now, calculating new SA:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (4.5)\\SA=8\pi + 18\pi\\SA= 26\pi$

Original SA is $44\pi$ ,

Halving diameter makes it $20\pi$

Halving height makes it $26\pi$

So, halving diameter does not have same effect as halving height.

5 0

3 years ago

how do you solve this: the sale price is $146.54 and the discount is 15% off. how do you solve for the original price?

N76 [4]

Mp. 146.54
dis . 15%
sp= 146.54 - 15 % of 146.54
=124.559

6 0

3 years ago

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,