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kap26 [50]
3 years ago
6

If I have 2 sticks of butter and need 2. How much do I need???

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0

You just stated how much you need. You need 2.

matrenka [14]3 years ago
5 0
You need two, you just stated whta you needed
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A number added to itself twelve times is five more than twice the number. What is the number?
zaharov [31]
x- \ searching\ number\\\\
x+12x=2x+5\\
13x-2x=5\\
11x=5\ |:11\\
x=\frac{5}{11}\\\\
The\ number\ is\ \frac{5}{11},

8 0
3 years ago
Plzzzzz help ASAP!!!!!!!!!
Alecsey [184]
I think it’s b the second one
5 0
4 years ago
Read 2 more answers
Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes
saveliy_v [14]

The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2 
we cannot have x equal to zero because the number can be infinite. 
So the LCD here is 10x, so multiply both sides by that to get: 
8x + 30 = 5x 
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3x = -30 
divide: 
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8 0
3 years ago
Let x and y be two positive numbers whose sum is 175 and (x+3)(y+4) is a maximum
Vaselesa [24]

Answer:

Step-by-step explanation:

x+y = 175

y = 175 - x

f(x) = (x+3)(y+4)

= x(175-x) + 3(175-x) + 4x + 12

= 175x - x² + 525 - 3x + 4x + 12

= -x² +176x + 537

f'(x) = -2x + 176

maximum when x = 88

y = 175-x = 87

4 0
3 years ago
What are the solutions of the equation (x-3)^2 + 2(x-3) -8 = 0
Mariulka [41]
Expand and simplify
(x-3) (x-3) +2(x-3) -8=0
(x-3+2)(x-3)-8=0
(x-1)(x-3)-8=0
x^2 -4x +3-8=0
x^2 - 4x -5=0
x^2 -5x +x-5=0
x(x-5)+x-5=0
(x+1)(x-5)=0
x= - 1, 5
6 0
3 years ago
Read 2 more answers
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