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Bogdan [553]
3 years ago
8

Fill in the blanks to write this function when x=3

Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer: Answer is below! :D

You're welcome!

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What is the domain and range of x+5
Genrish500 [490]
The domain of a function is the set of all acceptable input values (X-values). The range of a function is the set of all output values (Y-values).
3 0
3 years ago
M(2,5) is the midpoint of RS. The coordinates of S are (3,9). What are the coordinates of R?
kobusy [5.1K]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ R(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad S(\stackrel{x_2}{3}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{3+x}{2}~~,~~\cfrac{9+y}{2} \right)~~=~~\stackrel{M}{(2~,~5)}\implies \begin{cases} \cfrac{3+x}{2}=2\\[1em] 3+x=4\\ \boxed{x = 1}\\ \cline{1-1} \cfrac{9+y}{2}=5\\[1em] 9+y=10\\ \boxed{y=1} \end{cases}

5 0
3 years ago
Does anyone know how to solve this?
erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0
3 years ago
Resultado de esta cuenta Explicada cuenta completa:<br><br>(6+3)²=​
Mumz [18]

81 is the correct answer

hope it helps you have a good day

7 0
3 years ago
What is the equation of the line described below written in slope-iWhat is the equation of the line described below written in s
horsena [70]

The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

<h3>Equation of a line</h3>

A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;

y - y1 = -1/m(x-x1)

where

m is the slope

(x1, y1) is the intercept

Given the following

Point = (4, -1)

Line: 2x-y - 7 = 0


Determine the slope

-y = -2x + 7

y= 2x - 7

Slope = 2

Substitute

y+1 = -1/2(x -4)

Write in slope-intercept form

2(y + 1) = -(x - 4)

2y+2 = -x + 4

2y = -x + 2

y = -1/2 + 1

Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ1

4 0
2 years ago
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