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3 years ago

22 = 3x - 10 and 23 = x + 30 x = [?]

Mathematics

1 answer:

Vlad [161]3 years ago

7 0

Answer:

Step-by-step explanation:

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Mazyrski [523]

She should use 13 factors.
All 13 factors are the same thing . . . 7 .

7^13 should be written as 7¹³ .

It means: 7·7·7 · 7·7·7 · 7·7·7 · 7·7·7 · 7

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3 years ago

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9/16= what to the power of 2

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The answer to this is 3/4.

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3 years ago

Anna baked 3 batches of cookies with c cookies in each batch. She then ate 8 cookies! How many cookies does Anna have left? Writ

borishaifa [10]

Answer:

$3c-8$

Step-by-step explanation:

Let

c-------> the number of cookies in each batch

we know that

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$3c$ ------> equation that represent the total number of cookies

If Anna ate $8$ cookies

then

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3 years ago

Please help thnk you.

Levart [38]

Hello!

You have to find what they multiplied to 18 to get 27

27 / 18 = 1.5

The multiplied the sides by 1.5 to get the second shape

6 * 1.5 = 9

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Hope this helps!

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2 years ago

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Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]

Anastaziya [24]

Answer:

$f_{avg}=e-1$

Step-by-step explanation:

We are given that a function

$f(x)=e^{\frac{x}{7}}$

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx$

$f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}$

By using the formula

$\int e^{ax}=\frac{e^{ax}}{a}$

$f_{avg}=(e-e^0)=e-1$

Because $e^0=1$

$f_{avg}=e-1$

Hence, the average value of function on interval [0,7]

$f_{avg}=e-1$

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3 years ago

22 = 3x - 10 and 23 = x + 30 x = [?]​

22 = 3x - 10 and 23 = x + 30 x = [?]