Answer:
72 dollars ÷ 4
4 hours ÷ 4
=
18 dollars
1 hour
=
18 dollars
hour
= 18 dollars per hour
Step-by-step explanation:
Answer:
? = 4
4 is the number missing on the right.
Step-by-step explanation:
Check out the 8 on left. It has become a 2 on the right. How did that happen?
What do you have to multiply the 2 by to get 8?
Before I answer, check out the 9 on the right. What did you have to multiply it by to get 36? The answer to that is 4 isn't it?
What about the 2. Don't you have to multiply it by 4 to get 8?
36 + 8 = 4(9 + 2) The distributive property on the right will produce the numbers on the left.
So ? = 4
Step 1
Find the area of one equilateral triangle
Applying the law of sines

in this problem
a=b=7 cm
C=60 degrees
so

cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
Answer:



Step-by-step explanation:

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

Now we are read to write that one part (the first three terms together) as a square:

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

They put it in ( )

I'm going to go ahead and combine those fractions now:

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

I'm going to square root both sides to rid of the square on the x+b/(2a) part:


Now subtract b/(2a) on both sides:

Combine the fractions (they have the same denominator):

A chart would include
x, y
-2, 0
-1, 1
0, 2
1, 3
2, 4
The graph would look like this (Image attached)