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3 years ago

PLS HELP THIS IS DUE IN 5 MINUTES!!!

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

9514 1404 393

Answer:

340 ft^2

Step-by-step explanation:

The length of one side is 1/4 of the perimeter, so is 10 ft.

The area of the base is the square of the length of the side:

base area = (10 ft)^2 = 100 ft^2

The lateral area is the area of four triangles, each with a base of 10 ft and a height of 12 ft.

lateral area = 4(1/2)(10 ft)(12 ft) = 240 ft^2

The total surface area is the sum of the base area and the lateral area:

surface area = base area + lateral area

surface area = (100 ft^2) +(240 ft^2) = 340 ft^2

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Ravi has 33 marbles his brother has twice as many how many marbles do they have all together

ycow [4]

Answer

Together, they have 99 marbles.

Explanation

Ravi has 33 marbles.

His brother has twice (two times) as many marbles as him. Ravi's brother has 33×2=66 marbles.

Together, they have 33+66=99 marbles.

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3 years ago

Round to nearest tenth

lesya [120]

If you're supposed to round the answer to the nearest tenth it will be 92.9

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3 years ago

Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

artcher [175]

For this case we must solve the following equation:

$\sqrt {4x ^ 2} - \sqrt {x ^ 2} = 6$

To solve we follow the steps below:

We square both sides of the equation squared:

$(\sqrt {4x ^ 2} - \sqrt {x ^ 2}) ^ 2 = 6 ^ 2\\(\sqrt {4x ^ 2}) ^ 2-2 (\sqrt {4x ^ 2}) (\sqrt {x ^ 2}) + (\sqrt {x ^ 2}) ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 2 * x ^ 2}) + x ^ 2 = 36\\4x ^ 2-2 (\sqrt {4x ^ 4}) + x ^ 2 = 36\\4x ^ 2-2 (2x ^ 2) + x ^ 2 = 36\\4x ^ 2-4x ^ 2 + x ^ 2 = 36\\x ^ 2 = 36\\x = \pm \sqrt {36}\\x = \pm6$

We choose the positive value because we talk about $. $x = 6$

Answer:

8 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

Nitella [24]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (5.7, 7.0).

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean, when the population standard deviation is not provided is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}$

The sample selected is of size, n = 50.

The critical value of t for 95% confidence level and (n - 1) = 49 degrees of freedom is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, 49}=2.000$

*Use a t-table.

Compute the sample mean and sample standard deviation as follows:

$\bar x=\frac{1}{n}\sum {x}=\frac{1}{50}\times [6+4+6+...+9+6]=6.34\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{50-1}\times 229.22}=2.163$