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aleksandrvk [35]
3 years ago
10

If the mEDG = 25°, then find the measures of the following angles.

Mathematics
1 answer:
Serga [27]3 years ago
3 0

Answer:

m/BGA=25%3 EGG=GB7 EGF=CE6 BGE=BAF9

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A cone has a diameter of 4 cm and a height of 11 cm. What is the volume 1 point
anzhelika [568]

Answer: 46.05

Step-by-step explanation:

1/3 * 3.14 * 4 * 11 = 46.05 (rounded to the tenth)

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A000<br> 1<br> -1-1-1-1<br> AAA<br> A<br> 1<br> 1<br> 1<br> 1<br> 1<br> -1 (-1)(-1
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A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening
-BARSIC- [3]

Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

Where C : children, S : students and A : adults

The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\\3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]

The new system :

C-A=150\\S+2A=600

Working with the equations :

C = 150 + A\\S = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

C = 150 + 0 \\C = 150\\S = 600 - 2A\\S = 600

This verify the totaled receipts equation :

150($3)+600($5) = $ 3450

A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

From the equation :

S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

300≥ A

A is restricted to the interval [ 0, 300]

When A = 0 ⇒ C = 150

When A = 300 ⇒C = 150 + A = 150 + 300 = 450

Children ∈ [ 150,450]

With C being an integer number (including 0)

Also S and A are integer numbers (including 0)

7 0
3 years ago
The average weight of a medium size egg is found to be 3.2 oz, with a standard deviation of 0.13 oz. What is the heaviest egg (t
Over [174]

Answer:

We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz

Step-by-step explanation:

Mean = 3.2 oz, sd = 0.13 oz

Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303

Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz

Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz

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3 years ago
The quadrilateral with the following vertices is a
Vesna [10]

Answer:

Parallelogram

Step-by-step explanation: You have to plot the points in a coordinate plane. If you do that and connect the dots you will get parallelogram.

8 0
3 years ago
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