Last one I need help in will give BRAINLY (don’t send me links)
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Given =
Two similar pyramid have base area of 12.2 cm² and 16 cm².
surface area of the larger pyramid = 56 cm²
find out the surface area of the smaller pyramid
To proof =
Let us assume that the surface area of the smaller pyramid be x.
as surface area of the larger pyramid is 56 cm²
Two similar pyramid have base area of 12.2 cm² and 16 cm².
by using ratio and proportion
we have
ratio of the base area of the pyramids : ratio of the surface area of the pyramids
x = 12.2 ×56×
by solvingthe above terms
we get
x =42.7cm²
Hence the surface area of the smaller pyramid be 42.7cm²
Hence proved
Hi there! :)
4x + 5x + 12 = 6(x - 2)
Combine like terms and distribute the coefficient outside of the parenthesis:
9x + 12 = 6(x) + 6(-2)
9x + 12 = 6x - 12
Subtract 6x from both sides:
9x - 6x + 12 = 6x - 6x - 12
3x + 12 = -12
Subtract 12 from both sides:
3x + 12 - 12 = -12 - 12
3x = -24
Divide both sides by 3:
3x/3 = -24/3
x = -8.