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3 years ago

Find the following sums. Please help.

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

5m-n-4p

4a^2+6x-3

Step-by-step explanation:

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

Combine like terms

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

(3-5+7)m +(-4+9-6)n +(7-6-5)p

5m-n-4p

a^2 -3x +1

a^2 +9x -6

2a^2 +0x +2

----------------------

Combine like terms

a^2 -3x +1

a^2 +9x -6

2a^2 +0x +2

----------------------

(1+1+2)a^2 +(-3+9+0)x +(1-6+2)

4a^2+6x-3

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Estimate the sum of 279 and 217

Shalnov [3]

280 + 220 = 500 is the answer

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3 years ago

Please help i'm not that good at math. Determine the number of real solutions for each system of equations.

ratelena [41]

System A has ONE real solution

System B has NO real solutions

System C has ONE real solution

7 0

3 years ago

Read 2 more answers

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Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

PLEASE HELP ASAP!!!!

kolbaska11 [484]

Answer:

Step-by-step explanation:

130-89= other angle whic is 41

6 0

2 years ago

I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!

Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = $\sqrt{44}$ units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = $\frac{adjacent}{hypotenuse}$

Cos A = $\frac{10}{12}$

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0

3 years ago